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Question: A point moves on the xy plane according to the law x = a sin ωt and y = a(1 – cosωt) where a and ω a...

A point moves on the xy plane according to the law x = a sin ωt and y = a(1 – cosωt) where a and ω are positive constants. Find the distance covered in time t0.

A

aωt0

B

2a2+2a2cosωt0\sqrt{2a^{2} + 2a^{2}\cos\omega t_{0}}

C

2a (sin ωt0/2)

D

2a (cos ωt0/2)

Answer

aωt0

Explanation

Solution

vx = aω cos ωt and

vy = a ω sint ωt

or v = aωcos cot i^\widehat{i} + aω sin ωtj^\widehat{j} or |v| = aω

s = |v|t0 = aωt0.