Question

A point moves in such a way that its distance from (1,–2) is always the twice from (–3,5), the locus of the point is.

• A. $3x^{2} + y^{2} + 26x + 44y - 131 = 0$
• B. $x^{2} + 3y^{2} - 26x + 44y - 131 = 0$
• C. $3(x^{2} + y^{2}) + 26x - 44y + 131 = 0$
• D. None of these

Answer 1

Answer: (C)

$3(x^{2} + y^{2}) + 26x - 44y + 131 = 0$

Answer 2

$( x - 1 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 2 ^ { 2 } \left[ ( x + 3 ) ^ { 2 } + ( y - 5 ) ^ { 2 } \right]$

$\Rightarrow 3 \left( x ^ { 2 } + y ^ { 2 } \right) + 26 x - 44 y + 131 = 0$.