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Question

Question: A point charge Q is placed at the corner of a square plate of side a then the flux through the squar...

A point charge Q is placed at the corner of a square plate of side a then the flux through the square plate is -

A

Q80\frac{Q}{8 \in_{0}}

B

Q40\frac{Q}{4 \in_{0}}

C

Q0\frac{Q}{\in_{0}}

D

Zero

Answer

Zero

Explanation

Solution

The electric field due to Q at any point of square plate will be along the plane of square therefore angle between electric field and area vector of plate is 900. \ f = 0