Question

A point charge q is placed at P(0, 0, a). The electric flux through CAB due to the electric field of q is f. Then–

• A. f = $\frac{q}{48\varepsilon_{0}}$
• B. f<$\frac{q}{48\varepsilon_{0}}$
• C. $\frac{q}{48\varepsilon_{0}}$<f>$\frac{q}{24\varepsilon_{0}}$
• D. f>$\frac{q}{24\varepsilon_{0}}$

Answer 1

Answer: (B)

f<$\frac{q}{48\varepsilon_{0}}$

Answer 2

The flux is greater in the nearer half of the square OACB.