Question
Question: A point charge causes an electric flux of \[ - 1.0 \times {10^3}\,{\text{N}}{{\text{m}}^{\text{2}}}{...
A point charge causes an electric flux of −1.0×103Nm2C - 1 to pass through a spherical Gaussian surface of 10.0cm radius centred on the charge.
(a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?
(b) What is the value of the point charge?
Solution
For part (a), we need to find the flux if the radius of the Gaussian surface is doubled, for this recall the formula for electric flux, observe how the electric flux is dependent on the radius of the Gaussian surface. For part (b) use the formula for electric flux in terms of charge to the value of the given point charge.
Complete step by step answer:
Given, electric flux ϕ=−1.0×103Nm2C - 1
Electric flux of a point charge can be written as,
ϕ=ε0q
q is the charge and ε0=8.85×10−12CN - 1m - 2 is the permittivity of free space.
(a) It is asked if the radius of the Gaussian surface is doubled, what will be the value of flux.
Let R be the radius of the Gaussian surface and when it is doubled it is changed to 2R. From the formula of electric flux that is ϕ=ε0q, we observe that electric flux is independent of the radius of the Gaussian surface. Therefore, the electric flux will remain same that is ϕ=−1.0×103Nm2C - 1.
(b) We asked to find the value of the point charge. Let q be the point charge.
Now, from the formula of electric flux we have,