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Physics Question on coulombs law

A point charge A of +10µC and another point charge B of +20µC are kept Im apart in free space. The electrostatic force on A due to B is F1→\overrightarrow{F_1}, and the electrostatic force on B due to A is F2→\overrightarrow{F_2}. Then

A

F1→=−2F2→\overrightarrow{F_1}=-2\overrightarrow{F_2}

B

F1→=−F2→\overrightarrow{F_1}=-\overrightarrow{F_2}

C

2F1→=−F2→2\overrightarrow{F_1}=-\overrightarrow{F_2}

D

F1→=F2→\overrightarrow{F_1}=\overrightarrow{F_2}

Answer

F1→=−F2→\overrightarrow{F_1}=-\overrightarrow{F_2}

Explanation

Solution

The correct answer is Option (B) : F1→=−F2→\overrightarrow{F_1}=-\overrightarrow{F_2}