Question

A plot of $log\ \frac {x}{m}$ versus $log \ p$ for the adsorption of a gas on a solid gives a straight line with slope equal to:

• A. - log k
• B. n
• C. $\frac {1}{n}$
• D. log k

Answer 1

Answer: (C)

$\frac {1}{n}$

Answer 2

$\frac {x}{m} =k_p^{\frac1n}$

∴ $\frac {log\ x}{m}$= $log\ k + \frac {1}{n}\ log\ p$

∴ plot of $log\ \frac {x}{m}$ vs $log\ p$ will be linear with slope = $\frac 1n$.

So, the correct option is (C): $\frac 1n$