Question

A player caught a cricket ball of mass 150 g moving at a speed of 20 m/s. If the catching process is completed in 0.1 s, the magnitude of force exerted by the ball on the hand of the player is:

• A. 150 N
• B. 3 N
• C. 30 N
• D. 300 N

Answer 1

Answer: (C)

30 N

Answer 2

The force exerted is:

$F = \frac{\Delta P}{\Delta t}.$

Here:
$\Delta P = m \cdot v - 0 = 150 \times 10^{-3} \cdot 20 \, \text{kg m/s},$
$F = \frac{150 \times 10^{-3} \cdot 20}{0.1}.$

$F = 30 \, \text{N}.$

Final Answer: 30 N.