Question

A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1s, the force of the blow exerted by the ball on the hand of the player is equal to :

• A. 150 N
• B. 3 N
• C. 30 N
• D. 300 N

Answer 1

Answer: (C)

30 N

Answer 2

This is the question based on impulse-momentum theorem. $\left|F. \Delta r\right|$=|change in momentum| $\Rightarrow\, \quad F \times0.1=\left|p_{f}-p_{t}\right|$ As the ball will stop after catching; $p_{i}=mv_{i}=0.15 \times20=3, p_{f} =0$ $\Rightarrow\, \quad F\times0.1=3\Rightarrow F=30N$