Question

A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to -

• A. 30 N
• B. 300 N
• C. 150 N
• D. 3 N

Answer 1

Answer: (A)

30 N

Answer 2

F = $\frac{\Delta p}{\Delta t} = \frac{150 \times 10^{–3} \times 20}{0.1} = 30N$