Question
Physics Question on work, energy and power
A plate of mass m, length b and breadth a is initially lying on a horizontal floor with length parallel to the floor and breadth perpendicular to the floor. The work done to exect it on its breadth is
A
mg[2b]
B
mg[a+2b]
C
mg[2b−a]
D
mg[2b+a]
Answer
mg[2b−a]
Explanation
Solution
Initial height of centre of gravity=2a Fmal heig t o centre o gravity =2b Work done=mg[2b−2a] =mg[2b−a]