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Question: A planet moves around the sun. At a given point P, it is closed from the sun at a distance \(v _ { 1...

A planet moves around the sun. At a given point P, it is closed from the sun at a distance v1v _ { 1 }. At another point Q. when it is farthest from the sun at a distance d2d _ { 2 }, its speed will be

A

d12v1d22\frac { d _ { 1 } ^ { 2 } v _ { 1 } } { d _ { 2 } ^ { 2 } }

B

d2v1d1\frac { d _ { 2 } v _ { 1 } } { d _ { 1 } }

C

d1v1d2\frac { d _ { 1 } v _ { 1 } } { d _ { 2 } }

D

d22v1d12\frac { d _ { 2 } ^ { 2 } v _ { 1 } } { d _ { 1 } ^ { 2 } }

Answer

d1v1d2\frac { d _ { 1 } v _ { 1 } } { d _ { 2 } }

Explanation

Solution

According to law of conservation of angular momentum mv1d1=mv2d2m v _ { 1 } d _ { 1 } = m v _ { 2 } d _ { 2 }

\therefore v2=d1v1d2v _ { 2 } = \frac { d _ { 1 } v _ { 1 } } { d _ { 2 } } .