Question
Physics Question on Ray optics and optical instruments
A planet is observed by an astronomical refracting telescope having an objective of focal length 16 m and an eyepiece of focal length 2 cm
A
the distance between the objective and the eyepiece is 16.02 m
B
the angular magnification of the planet is -800
C
the image of the planet is inverted
D
the objective is larger than the eyepiece
Answer
the objective is larger than the eyepiece
Explanation
Solution
Distance between objective and eyepiece L=fo+fe=(16+0.02)m=16.02m Angular magnification \hspace10mm M=-f_o/f_e=-16/0.02=-800 Image is inverted and objective is larger than the eyepiece.