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Question

Physics Question on thermal properties of matter

A planet having average surface temperature T0T_{0} at an average distance dd from the sun. Assuming that the planet receives radiant energy from the sun only and it loses radiant energy only from the surface and neglecting all other atmospheric effects we conclude

A

T0d2T_{0}\propto d^{2}

B

T0d2T_{0}\propto d^{-2}

C

T0d1/2T_{0}\propto d^{1/2}

D

T0d1/2T_{0}\propto d^{-1/2}

Answer

T0d1/2T_{0}\propto d^{-1/2}

Explanation

Solution

Energy received per second by the planet =P4πd2(πR2)=\frac{P}{4 \pi d^{2}}\left(\pi R^{2}\right) where, PP is power radiated by the sun and RR is the radius of the planet. Further, energy radiated per second by the planet according to Stefan's law is σ(4πR2)T04\sigma\left(4 \pi R^{2}\right) T_{0}^{4}. For thermal equilibrium to exist, we get P4πd2(πR2)=σ(4πR2)T04\frac{P}{4 \pi d^{2}}\left(\pi R^{2}\right)=\sigma\left(4 \pi R^{2}\right) T_{0}^{4} T04d2\Rightarrow T_{0}^{4} \propto d^{-2} T0d1/2\Rightarrow T_{0} \propto d^{-1 / 2}