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Question: A planet has mass \(\dfrac{1}{10}th\) of that of Earth, while radius is \(\dfrac{1}{3}rd\) of that o...

A planet has mass 110th\dfrac{1}{10}th of that of Earth, while radius is 13rd\dfrac{1}{3}rd of that of Earth. If a person can throw a stone on Earth surface to a height of 90m90m, then he will be able to throw the stone on that planet to a height-
(A). 90m90m
(B). 40m40m
(C). 300m300m
(D). 45m45m

Explanation

Solution

The force of gravity acting on the stone on Earth and the other planet will be different due to the difference in their masses and radii and hence acceleration due to gravity on their surfaces will also be different. Due to these factors the maximum height attained by the stone will also be different.

Formulae used:
F=GMmR2F=\dfrac{GMm}{{{R}^{2}}}
F=maF=ma
P=mghP=mgh

Complete step-by-step solution:
Every object exerts a force on another object; this force is known as the gravitational force. The gravitational force due to the Earth’s surface is given by-
F=GMmR2F=\dfrac{GMm}{{{R}^{2}}} (1)
Here,
FF is the gravitational force
MM is the mass of the Earth
mm is the mass of the body on or near the Earth’s surface
RR is distance between Earth and body
For objects on the Earth’s surface, RR is the radius of the Earth.

We know that, F=maF=ma, substituting in eq (1), we get,
ma=GMmR2 a=GMR2 g=GMR2 \begin{aligned} & ma=\dfrac{GMm}{{{R}^{2}}} \\\ & \Rightarrow a=\dfrac{GM}{{{R}^{2}}} \\\ & \therefore g=\dfrac{GM}{{{R}^{2}}} \\\ \end{aligned}
Here, gg is acceleration due to gravity

Given, a planet has mass M10\dfrac{M}{10} and radius R3\dfrac{R}{3}, then acceleration due to gravity on its surface will be-
g=GM10R3 g=310×GMR g=310g \begin{aligned} & g'=\dfrac{G\dfrac{M}{10}}{\dfrac{R}{3}} \\\ & \Rightarrow g'=\dfrac{3}{10}\times \dfrac{GM}{R} \\\ & \therefore g'=\dfrac{3}{10}g \\\ \end{aligned}
The other planet’s acceleration due to gravity is 310g\dfrac{3}{10}g

When a stone is thrown on Earth’s surface it reaches a height of 90m90m, its potential energy will be-
P=mgh P=m×10×90 P=900m \begin{aligned} & P=mgh \\\ & \Rightarrow P=m\times 10\times 90 \\\ & \therefore P=900m \\\ \end{aligned}

Therefore, the maximum potential energy that can be stored in the stone is 900mJ900m\,J. Using the potential energy, the maximum eight it can reach on the other planet is-
mgh=900m gh=900 310gh=900 310×10h=900 h=300m \begin{aligned} & mg'h'=900m \\\ & \Rightarrow g'h'=900 \\\ & \Rightarrow \dfrac{3}{10}gh'=900 \\\ & \Rightarrow \dfrac{3}{10}\times 10h'=900 \\\ & \therefore h'=300m \\\ \end{aligned}
Therefore, the maximum height which the stone can reach on the other planet is 300m300m.

Hence, the correct option is (C).

Note:
The nature of gravitational force is always attractive. The energy stored in a body by virtue of its position is called its potential energy. Gravitational force exists between all bodies but its magnitude is very small, for larger bodies like Earth, due to their large masses, their force is prominent