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Question: A plane polarized light entering according to equation x + y + z = constant. angle made with x-axis ...

A plane polarized light entering according to equation x + y + z = constant. angle made with x-axis is

A

sin1^{-1}(13\frac{1}{\sqrt{3}})

B

cos1^{-1}(13\frac{1}{\sqrt{3}})

C

cos1^{-1}(14\frac{1}{\sqrt{4}})

D

sin1^{-1}(14\frac{1}{\sqrt{4}})

Answer

cos1^{-1}(13\frac{1}{\sqrt{3}})

Explanation

Solution

The wavefront is given by

x+y+z=constant.x+y+z=\text{constant}.

The normal to this plane is n=(1,1,1)\vec{n}=(1,1,1). For plane polarized light, the direction of propagation is along the normal. The angle θ\theta between n\vec{n} and the xx-axis is given by:

cosθ=nxn=112+12+12=13.\cos\theta=\frac{n_x}{|\vec{n}|}=\frac{1}{\sqrt{1^2+1^2+1^2}}=\frac{1}{\sqrt{3}}.

Thus,

θ=cos1(13).\theta = \cos^{-1}\left(\frac{1}{\sqrt{3}}\right).