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Question: A plane monochromatic light falls on a diaphragm normally on two slits separated by a distance of 2....

A plane monochromatic light falls on a diaphragm normally on two slits separated by a distance of 2.5 mm. The fringe pattern formed on a screen at 1 m distance displaces due to glass plate (m = 3/2) of thickness 10 mm placed in front of one slit. Then value of displacement is –

A

1 mm

B

2 mm

C

3 mm

D

4 mm

Answer

2 mm

Explanation

Solution

Shift = (m _ 1) t . Dd\frac{D}{d}

= (321)\left( \frac{3}{2} - 1 \right)× 10×106×12.5×103\frac{10 \times 10^{–6} \times 1}{2.5 \times 10^{–3}}

= 2 mm