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Question: A plane meets the coordinate axes at A, B, C and the foot of the perpendicular from the origin O to ...

A plane meets the coordinate axes at A, B, C and the foot of the perpendicular from the origin O to the plane is P, OA = a, OB = b, OC = c. If P is the centroid of the triangle ABC, then –

A

a + b + c = 0

B

|a| = |b| = |c|

C

1a+1b+1c\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = 0

D

None of these

Answer

|a| = |b| = |c|

Explanation

Solution

Let equation of the plane is

xa+yb+zc\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1 … (1)

Co-ordinates of P is(a3,b3,c3)\left( \frac{a}{3},\frac{b}{3},\frac{c}{3} \right)

Q OP is ^ to the plane

\ OP is parallel to normal to the plane (1)

\ a/31/a\frac{a/3}{1/a} = b/31/b\frac{b/3}{1/b} = c/31/c\frac{c/3}{1/c}

Ž a2 = b2 = c2

Ž |a| = |b| = |c|.