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Question: A plane electromagnetic wave travels in free space along X-direction. If the value of \(\overrightar...

A plane electromagnetic wave travels in free space along X-direction. If the value of B\overrightarrow{B} (in tesla) at a particular point in space and time is 1.2×10-8k, the value of E\overrightarrow{E} (in Vm1m^{- 1}) at that point is:

A

1.2j^1.2\widehat{j}

B

3.6j^3.6\widehat{j}

C

1.2k^1.2\widehat{k}

D

3.6j^3.6\widehat{j}

Answer

3.6j^3.6\widehat{j}

Explanation

Solution

: Here, B=1.2×108k^T\overrightarrow{B} = 1.2 \times 10^{- 8}\widehat{k}T

The magnitude of E\overrightarrow{E} is

E=Bc=(1.2×108T)(3×108ms1)E = Bc = (1.2 \times 10^{- 8}T)(3 \times 10^{8}ms^{- 1})

=3.6Vm1= 3.6Vm^{- 1}

B\overrightarrow{B} is along Z – direction and the wave propagates along X – direction. Therefore E\overrightarrow{E}should be in a direction perpendicular to both X and Z axes. Using vector algebra E×B\overrightarrow{E} \times \overrightarrow{B}should be along Z – direction.

Thus, E=3.6J^Vm1\overrightarrow{E} = 3.6\widehat{J}Vm^{- 1}