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Question

Physics Question on electrostatic potential and capacitance

A plane electromagnetic wave of frequency 50MHz50\, MHz travels in free space along the positive xx-direction. At a particular point in space and time, E=6.3j^V/m\vec{E} = 6.3 \hat{j} V/m . The corresponding magnetic field B\vec{B} , at that point will be:

A

18.9×108k^T18.9 \times 10^{-8} \hat{k} T

B

6.3×108k^T6.3 \times 10^{-8} \hat{k} T

C

2.1×108k^T2.1 \times 10^{-8} \hat{k} T

D

18.9×108k^T18.9 \times 10^{8} \hat{k} T

Answer

2.1×108k^T2.1 \times 10^{-8} \hat{k} T

Explanation

Solution

B=EC=6.33×108=2.1×108T\left|B\right| = \frac{\left|E\right|}{C} = \frac{6.3}{3 \times10^{8}} =2.1 \times10^{-8} T
and E^×B^=C^\hat{E} \times\hat{B} = \hat{C}
j^×B^=i^\hat{j} \times\hat{B} =\hat{i}
B^=k^\hat{B} = \hat{k}
B=BB^=2.1×108k^T\vec{B} = \left| B\right|\hat{B} = 2.1 \times10^{8} \hat{k} T