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Question: A piston of mass \(M_0\) can slide along axis of a cylinder of cross-section area 'A'. Cylinder is k...

A piston of mass M0M_0 can slide along axis of a cylinder of cross-section area 'A'. Cylinder is kept horizontal and contains n moles of monoatomic gas at pressure P0P_0. Assume piston is made of conducting material. When piston is slightly displaced it performs SHM with angular frequency ω\omega. Then mass of piston is

Answer

M_0=\frac{A^2P_0^2}{nRT,\omega^2}

Explanation

Solution

  1. For an isothermal process, PV=nRTPV=nRT implies

    V0=nRTP0.V_0=\frac{nRT}{P_0}.
  2. A small displacement xx causes

    PP0(1AxV0).P\approx P_0\left(1-\frac{Ax}{V_0}\right).
  3. Restoring force:

    FA2P0V0x.F\approx -\frac{A^2P_0}{V_0}\,x.
  4. With ω2=kM0\omega^2=\frac{k}{M_0}, solve for M0M_0 to get:

    M0=A2P02nRTω2.M_0=\frac{A^2P_0^2}{nRT\,\omega^2}.