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Question

Physics Question on Oscillations

A piston is performing S.H.M. in the vertical direction with a frequency of 0.5 Hz. A block of 10 kg is placed on the piston. The maximum amplitude of the system such that the block remains in contact with the piston is

A

1.5 m

B

1 m

C

0.1 m

D

0.5 m

Answer

1 m

Explanation

Solution

f=0.5Hzf=0.5 Hz
ω=2πf=π\omega=2 \pi f=\pi
for block to remain in contact with the piston at amplitude position weight A the block = Force due to oscillation.
mg = ma
mg=m(ω2A)mg=m\left(\omega^{2}A\right)
A=gω2=10π2=1mA=\frac{g}{\omega^{2}}=\frac{10}{\pi^{2}}=1 m