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Question

Physics Question on Electromagnetic waves

A piston filled in cylindrical pipe is pulled as shown in the figure. A tuning fork is sounded at open end and loudest sound is heard at open length 13cm,41cm13\, cm,41\, cm and 69cm69 \,cm. The frequency of tuning fork, if velocity of sound is 350ms1350\, ms^{-1} is

A

1250 Hz

B

625 Hz

C

417 Hz

D

715 Hz

Answer

625 Hz

Explanation

Solution

In a closed organ pipe in which length of air-column can be increased or decreased.
The first resonance occurs at λ/4\lambda / 4 and second resonance occurs at 3λ/43 \lambda / 4
Thus, at first resonance
40mmλ4=1345mm(i)40\,mm \frac{\lambda}{4} = 13 45\,mm\, \dots (i)
and at second resonance
40mm3λ4=4145mm(ii)40\,mm \frac{3 \lambda}{4} = 41 45\,mm \dots (ii)
Subtracting E (i) from E (ii), we have
30mm3λ4λ4=411330\,mm \frac{3 \lambda}{4} - \frac{\lambda}{4} = 41 - 13
30mmλ2=28\Rightarrow 30\,mm \frac{\lambda}{2} = 28
30mmλ=56cm\therefore 30\,mm \lambda = 56 \, cm
Hence, frequency of tuning for kk
30mmn=vλ=35056×102=625Hz30\,mm n = \frac{v}{\lambda} = \frac{350}{56 \times 10^{-2}} = 625 \, Hz