Question
Question: A pipe ABCD of uniform cross-section is bent into three sections, viz., a horizontal section AB, a v...
A pipe ABCD of uniform cross-section is bent into three sections, viz., a horizontal section AB, a vertical section BC with C below B, and a horizontal section CD. Liquid flowing through the pipe has speed v1 and pressure p1 in section AB, and speed v2 and pressure p2 in section CD –
A
(a) v1 = v2, p1 = p2
A
(b) v1= v2, p2> p1
A
(c) v2> v1, p2> p1
A
(d) v2> v1, p1 = p2
Explanation
Solution
(b)
v1 = v2 (equation of continuity)
Also; 
+ gh + 
= 
+ 0 + 
P2 – P1 = hrg \ P2 > P1