Question

A piece of wire of resistance $R$ is cut into n equal parts. These parts are then connected in parallel. If the equivalent resistance of the parallel combination is $R'$ , then $\big(\frac{R}{R'}\big)$ is

• A. $\frac{1}{1}$
• B. $\frac{n}{1}$
• C. $\frac{n^2}{1}$
• D. $\frac{1}{n}$

Answer 1

Answer: (C)

$\frac{n^2}{1}$

Answer 2

Resistance, $R=\frac{\rho l}{A}$
If $r$ be the resistance of one cut part, then
$r=\frac{\rho(l / n)}{A}=\frac{R}{n}$
The resistance $R^{'}$ of the parallel combination is given by
$\frac{1}{R^{'}}=\frac{1}{r}+\frac{1}{r}+\ldots=\frac{n}{r}$
So, $R^{'}=\frac{r}{n}=\frac{R / n}{n}=\frac{R}{n^{2}}$
Hence, $\frac{R}{R^{'}}=\frac{n^{2}}{1}$