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Question: A piece of solid weighs 120 g in air, 80 g in water and 60 kg in a liquid. The relative density of t...

A piece of solid weighs 120 g in air, 80 g in water and 60 kg in a liquid. The relative density of the solid and that of the liquid are respectively.

A

B

C

D

Answer

Explanation

Solution

Relative density of solid

=12012080=12040=3= \frac { 120 } { 120 - 80 } = \frac { 120 } { 40 } = 3

Relative density of liquid

= weight in air  weight in liquid  weight in air  weight in water = \frac { \text { weight in air } - \text { weight in liquid } } { \text { weight in air } - \text { weight in water } }

=1206012080=6040=32= \frac { 120 - 60 } { 120 - 80 } = \frac { 60 } { 40 } = \frac { 3 } { 2 }

=12012080=12040=3= \frac { 120 } { 120 - 80 } = \frac { 120 } { 40 } = 3