Solveeit Logo
Login

Question

Physics Question on mechanical properties of fluid

A piece of solid weighs 120 g120\, g in air, 80 g80\, g in water and 60 kg60\, kg in a liquid. The relative density of the solid and that of the liquid are respectively

A

2,122, \frac{1}{2}

B

2,322, \frac{3}{2}

C

3,123, \frac{1}{2}

D

3,323, \frac{3}{2}

Answer

3,323, \frac{3}{2}

Explanation

Solution

Relative density of solid =weight in airweight in air ? weight in water =\frac{\text{weight in air}} {\text{weight in air ? weight in water }} =120120−80=12040=3=\frac{120}{120-80}=\frac{120}{40}=3 Relative density of liquid =weight in air - weight in liquidweight in air - weight in water=\frac{\text{weight in air - weight in liquid}} {\text{weight in air - weight in water}} =120−60120−80=6040=32=\frac{120-60}{120-80}=\frac{60}{40}=\frac{3}{2}