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Question: A piece of metal floats on Hg. The coefficient of expansion of metal and Hg are g<sub>1</sub> and g<...

A piece of metal floats on Hg. The coefficient of expansion of metal and Hg are g1 and g2 respectively. If the temperature of both Hg and metal are increased by an amount DT, by what factor the fraction of the volume of metal submerged in mercury changes?

A

(g2 – g1) DT

B

(γ2+γ12)\left( \frac{\gamma_{2} + \gamma_{1}}{2} \right)DT

C

2γ1γ2γ1+γ2\frac{2\gamma_{1}\gamma_{2}}{\gamma_{1} + \gamma_{2}}DT

D

γ1γ2γ1+γ2\frac{\gamma_{1}\gamma_{2}}{\gamma_{1} + \gamma_{2}}DT

Answer

(g2 – g1) DT

Explanation

Solution

fin = VinV\frac{V_{in}}{V} = Δff\frac{\Delta f}{f} = finfinfin\frac{f'_{in}–f_{in}}{f_{in}}

= finfin\frac{f'_{in}}{f_{in}} – 1

= ρσ(1+γ2ΔT1+γ1ΔT)1ρ/σ\frac{\frac{\rho}{\sigma}\left( \frac{1 + \gamma_{2}\Delta T}{1 + \gamma_{1}\Delta T} \right)–1}{\rho/\sigma}

= (g2 – g1) DT (using Binomial theorem)