Question

A piece of fuse wire melts when a current of 15 ampere flows through it. With this current, if it dissipates 22.5 W, the resistance of fuse wire will be

• A. Zero
• B. $10\Omega$
• C. $1\Omega$
• D. $0.10\Omega$

Answer 1

Answer: (D)

$0.10\Omega$

Answer 2

$P = i^{2}R$ ⇒ $22.5 = (15)^{2} \times R$ ⇒ $R = 0.10\Omega$