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Question

Physics Question on The gravitational constant

A physical quantity of the dimensions of length that can be formed out of c, G and e24πε0\frac {e^2}{4πε_0} is
[c is velocity of light, G is universal constant of gravitation and e is charge]

A

1c2[Ge24πε0]12\frac {1}{c^2}[G\frac {e^2}{4πε_0}]^{\frac 12}

B

c2[Ge24πε0]12c^2[G\frac {e^2}{4πε_0}]^{\frac 12}

C

1c2[e2G4πε0]12\frac {1}{c^2}[\frac {e^2}{G4πε_0}]^{\frac 12}

D

1cGe24πε0\frac {1}{c}G\frac {e^2}{4πε_0}

Answer

1c2[Ge24πε0]12\frac {1}{c^2}[G\frac {e^2}{4πε_0}]^{\frac 12}

Explanation

Solution

The correct option is (A): 1c2[Ge24πε0]12\frac {1}{c^2}[G\frac {e^2}{4πε_0}]^{\frac 12}.