Question

A photon, whose energy is 14 eV, is allowed to interact with a hydrogen atom in its ground state. Then –

• A. The photon is absorbed by the H-atom, resulting in ionization of H-atom, and the outgoing electron has 0.4 eV energy
• B. Since photon energy is greater than 13.6 eV, it can not be absorbed by the atom
• C. The photon is absorbed by the atom and then it reemits two photons each of energy 7 eV
• D. None of these

Answer 1

Answer: (A)

The photon is absorbed by the H-atom, resulting in ionization of H-atom, and the outgoing electron has 0.4 eV energy

Answer 2

E_ph = 14 eV

$K.E_{e^{-}}$= 14 – 13.6 = 0.4 eV