Question
Question: A photoelectric surface is illuminated successively by monochromatic light of wavelength \[\lambda \...
A photoelectric surface is illuminated successively by monochromatic light of wavelength λ and 2λ. If the maximum kinetic energy of the emitted photoelectrons in the second case is 3 times than in the first case, the work function of the surface of the material is.
(h=Planck’s constant and c= Speed of Light)
(A) 3λhc
(B) 2λhc
(C) λhc
(D) 4λhc
Solution
Use Einstein’s photoelectric equation to find the maximum kinetic energy. Apply the given conditions in the question to obtain the expression for work function.
Complete step by step solution:
Let us assume that W is the work function material on the surface
According to Einstein’s Photoelectric Equation,
KEmax=λhc−W------ (1)
Now, when λ becomes 2λ in the second case, the equation changes into,
KE2max=λhc−W=λ2hc−W -------- (2)
It is given in the question that the maximum kinetic energy of photons emitted in the second case is 3 times the first case.
Therefore,
KE2max=3×KEmax
Substituting KEmax value from equation (1), we get
KE2max=3×(λhc−W)
⇒λ2hc−W=λ3hc−3W
⇒2W=λhc
∴W=2λhc
Hence, the work function W is given as 2λhc.
Option (B) is the right answer.
Note: The photoelectric effect is the emission of electrons, when electromagnetic radiation hits the material. Electrons emitted are called photoelectrons. Above the specified frequency value, the strength of the photoelectric current depends on the light radiation intensity. Any frequency value below the specified value will be unable to produce photoelectrons or photoelectric current.
Albert Einstein said that a beam of light will not propagate as waves rather it propagates as discrete packets of waves called as photons. It stated that light is a collection of quantum radiation. Einstein combined his theory with the photoelectric concept put forward by Max Planck. He states that each