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Question: A person uses a lens of power + 3D to normalise vision. Near point of hypermetropic eye is...

A person uses a lens of power + 3D to normalise vision. Near point of hypermetropic eye is

A

1 m

B

1.66 m

C

2 m

D

0.66 m

Answer

1 m

Explanation

Solution

Focal length of the lens

By lens formula 1f=1v−1u\frac { 1 } { f } = \frac { 1 } { v } - \frac { 1 } { u }

⇒1+100/3=1v−1−25⇒v=−100 cm=−1 m\Rightarrow \frac { 1 } { + 100 / 3 } = \frac { 1 } { v } - \frac { 1 } { - 25 } \Rightarrow v = - 100 \mathrm {~cm} = - 1 \mathrm {~m}