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Question

Physics Question on speed and velocity

A person travelling in a straight line moves with a constant velocity v1 for certain distance 'x' and with a constant velocity v2v_2 for next equal distance. The average velocity v is given by the relation

A

1v=1v1+1v2\frac{1}{v}=\frac{1}{v_{1}}+\frac{1}{v_{2}}

B

2v=1v1+1v2\frac{2}{v}=\frac{1}{v_{1}}+\frac{1}{v_{2}}

C

v2=v1+v22\frac{v}{2}=\frac{v_{1}+v_{2}}{2}

D

v=v1v2v=\sqrt{v_{1}v_{2}}

Answer

2v=1v1+1v2\frac{2}{v}=\frac{1}{v_{1}}+\frac{1}{v_{2}}

Explanation

Solution

Average velocity =Total distanceTotal time= \frac{\text{Total distance}}{\text{Total time}} =X+XXV1+XV2 = \frac{X + X}{ \frac{X}{V_1} + \frac{X}{V_2}} v=21v1+1v2\Rightarrow v = \frac{2}{\frac{1}{v_1} + \frac{1}{v_2}} 2v=1v1+1v2 \Rightarrow \frac{2}{v} = \frac{1}{v_1} + \frac{1}{v_2}