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Question

Question: A person observes the angle of deviation of a building as \(30 ^ { \circ }\). The person proceeds to...

A person observes the angle of deviation of a building as 3030 ^ { \circ }. The person proceeds towards the building with a speed of 4545 ^ { \circ }. The height of the building (in metres) is

A

100

B

50

C

50(3+1)50 ( \sqrt { 3 } + 1 )

D

50(31)50 ( \sqrt { 3 } - 1 )

Answer

50

Explanation

Solution

In \Rightarrow 13=h50(31)+h\frac { 1 } { \sqrt { 3 } } = \frac { h } { 50 ( \sqrt { 3 } - 1 ) + h }

3h=50(31)+h\sqrt { 3 } h = 50 ( \sqrt { 3 } - 1 ) + h

h=50h = 50 metre