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Question: A person moves 30 m north, then 30 m east, then \(30 \sqrt { 2 }\)south-west. His displacement from ...

A person moves 30 m north, then 30 m east, then 30230 \sqrt { 2 }south-west. His displacement from the original position is

A

Zero

B

28 m towards south

C

10 m towards west

D

15 m towards east

Answer

Zero

Explanation

Solution

Resolving displacement 30230 \sqrt { 2 }m south-west into two rectangular components, we get

Displacement in south

=302cos45=302×(12)=30 m= 30 \sqrt { 2 } \cos 45 ^ { \circ } = 30 \sqrt { 2 } \times \left( \frac { 1 } { \sqrt { 2 } } \right) = 30 \mathrm {~m}

Displacement in west

=302sin45=302×(12)=30 m= 30 \sqrt { 2 } \sin 45 ^ { \circ } = 30 \sqrt { 2 } \times \left( \frac { 1 } { \sqrt { 2 } } \right) = 30 \mathrm {~m}

\thereforeEffective displacement due to 30m north and 30 m south is zero.

Also effective displacement due to 30m north and 30 m west is zero.