Question

A person goes 10 km north and 20 km east. What will be displacement from initial point

• A. 22.36 km
• B. 2 km
• C. 5 km
• D. 20 km

Answer 1

Answer: (A)

22.36 km

Answer 2

$\overset{\rightarrow}{AC} = \overset{\rightarrow}{AB} + \overset{\rightarrow}{BC}$

$AC = \sqrt{(AB)^{2} + (BC)^{2}}$

$= \sqrt{(10)^{2} + (20)^{2}}$

$= \sqrt{100 + 400} = \sqrt{500} = 22.36km$