Question

A person draws a card from a pack of playing card, replaces it and shuffles the pack. He continues doing this until he shows a spade. The chance that he will fail in the first two trial is

• A. 9/64
• B. 1/64
• C. 1/16
• D. 9/16

Answer 1

Answer: (A)

9/64

Answer 2

Required probability = $\frac { { } ^ { 39 } \mathrm { C } _ { 1 } } { { } ^ { 52 } \mathrm { C } _ { 1 } } \times \frac { { } ^ { 39 } \mathrm { C } _ { 1 } } { { } ^ { 52 } \mathrm { C } _ { 1 } } \times \frac { { } ^ { 13 } \mathrm { C } _ { 1 } } { { } ^ { 53 } \mathrm { C } _ { 1 } } = \frac { 9 } { 64 }$