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Question: A person adds \(1.71grams\) of sugar \(({C_{12}}{H_{22}}{O_{11}})\) in order to sweeten his tea. The...

A person adds 1.71grams1.71grams of sugar (C12H22O11)({C_{12}}{H_{22}}{O_{11}}) in order to sweeten his tea. The number of carbon atoms added is (Mol. mass of sugar = 342):
A.3.6×10223.6 \times {10^{22}}
B.7.2×10217.2 \times {10^{21}}
C.0.050.05
D.6.6×10226.6 \times {10^{22}}

Explanation

Solution

As indicated by mole concept one mole of atoms = subatomic mass in grams and number of atoms = number of moles ×\times Avogadro's number and so the quantity of atoms is given by the equation = number of moles of substance ×\times avo. Number.

Complete answer:
We know that the quantity of moles is the proportion of mass to molar mass.
Then the moles of sugar is equal to 1.71342=1200mol\dfrac{{1.71}}{{342}} = \dfrac{1}{{200}}mol
Now, we need to calculate the number of molecules NA{N_A} and this is given by the product of number of moles and Avogadro’s number as:
NA=6.023×1023{N_A} = 6.023 \times {10^{23}}
Hence, the number of molecules is equal to 1200×NA\dfrac{1}{{200}} \times {N_A}
Now let us calculate the number of C atoms in the molecule, and this can be done by using:
Number of C atoms in the molecule = 12×1200×NA12 \times \dfrac{1}{{200}} \times {N_A}
As we know the value of NA{N_A} let us substitute that in the above and then the value becomes:
3.6×1022\Rightarrow 3.6 \times {10^{22}}

Thus, the correct answer to the above question is option A.

Note:
Where n is the quantity of moles of the substance (or rudimentary element), NN is the complete number of rudimentary elements in the example, and NA{N_A}is the Avogadro steady. "Mole" was presented around the year 1896 by the German scientist Wilhelm Ostwald, who got the term from the Latin word moles meaning a 'store' or 'heap.