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Physics Question on Magnetism and matter

A permanent magnet in the shape of a thin cylinder of length 50 cm50 \,cm has intensity of magnetisaton 106 A m−110^6\, A\, m^{-1}. The magnetisation current is

A

5×105 A5 \times 10^5\, A

B

6×105 A6 \times 10^5\, A

C

5×104 A5 \times 10^4\, A

D

6×104 A6 \times 10^4\, A

Answer

5×105 A5 \times 10^5\, A

Explanation

Solution

Here, l=50 cm=0.5 ml = 50\, cm = 0.5 \,m, M=106 A m−1M = 10^6\, A\, m^{-1} As M=magnetisation current(IM)l(length)M = \frac{magnetisation \,current \left(I_{M}\right)}{l\left( length\right)} Then, IM=M×l=106×0.5=5×105 AI_{M }= M \times l = 10^{6} \times 0.5 = 5 \times 10^{5} \,A.