Question

A perfect gas at 27⁰C is heated at constant pressure to 327⁰C. If original volume of gas at 27⁰C is V then volume at 327⁰C is

• A. V
• B. 3V
• C. 2V
• D. V/2

Answer 1

Answer: (C)

2V

Answer 2

From Charle’s law $V \propto T$ ∴ $\frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}} = \frac{327 + 273}{27 + 273} = \frac{600}{300} = 2$ ⇒ $V_{2} = 2V.$