Question

A perfect gas at 27°C is heated at constant pressure so as to triple its volume. The temperature of the gas will be

• A. 81°C
• B. 900°C
• C. 627°C
• D. 450°C

Answer 1

Answer: (C)

627°C

Answer 2

$V \propto T$Ž $\frac{V_{1}}{V_{2}} = \frac{T_{1}}{T_{2}}$ Ž $\frac{V}{3V} = \frac{(273 + 27)}{T_{2}}$

Ž $T_{2} = 900K$ ® 627°C [$\because$T(K) = 273 + t°C]