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Question: A pendulum is vibrating with an amplitude of π/2 radian. Value of αfor which resultant acceleration ...

A pendulum is vibrating with an amplitude of π/2 radian. Value of αfor which resultant acceleration of the bob directs along the horizontal is

A

sin-1/3\sqrt{3}

B

cos-11/3\sqrt{3}

C

cos-13\sqrt{3}/2

D

sin-13\sqrt{3}/2

Answer

cos-11/3\sqrt{3}

Explanation

Solution

Tangential acceleration, at = g sin α and radial

acceleration,

ar = v2l=2glcosαl\frac{v^{2}}{l} = \frac{2gl\cos\alpha}{l} = 2 g cos α

Also tan α = arat\frac{a_{r}}{a_{t}}

= 2gcosαgsinα=2tanα\frac{2g\cos\alpha}{g\sin\alpha} = \frac{2}{\tan\alpha}

or tan2α = 2 i.e., sec2 α = 3

or 1cos2α=3\frac{1}{\cos^{2}\alpha} = 3 or cos α = 13\frac{1}{\sqrt{3}}

or α = cos-113\frac{1}{\sqrt{3}}