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Question: A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro lik...

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20ms220m{s^{ - 2}} at a distance of 5m from the moving position. The time period of oscillation is?
(A) 2s
(B) 2πs2\pi s
(C) 1s
(D) πs\pi s

Explanation

Solution

Pendulum is a weight suspended from a fixed point in such a way that it can swing. A simple harmonic oscillator consists of a mass, which experiences a force FF which pulls the mass in its equilibrium position.
A simple pendulum is a simple harmonic oscillator for a small angle.

Formula used:
a=ω2xa = {\omega ^2}x ;
This is the equation of motion for a simple harmonic oscillator. Where ‘aa’ is acceleration, ω\omega is angular frequency and xx is the displacement from the mean position.
ω=2πT\omega = \dfrac{{2\pi }}{T} ;
This is the relation between angular frequency and time period of oscillation.

Complete step by step solution:
So according to the question the pendulum is displaced with a small angle so that it performs harmonic oscillation. The equation of motion for harmonic oscillation is given below.
a=ω2xa = {\omega ^2}x
Where ‘aa’ is acceleration, ω\omega is the angular frequency and xx is the displacement from the mean position.
Following information is given in the question, a=20ms2a=20m{s^{ - 2}} and x=5mx=5m.
Now let us use the formula a=ω2xa = {\omega ^2}x and substitute the values in it.
20=ω2520 = {\omega ^2}5
Let us further simplify it.
ω2=205=4{\omega ^2} = \dfrac{{20}}{5} = 4
ω=2s1\Rightarrow \omega = 2{s^{ - 1}}
As we got the value of angular frequency, let us use the formula ω=2πT\omega = \dfrac{{2\pi }}{T} to find the time period.
The time period is the time taken by the pendulum to complete one complete rotation or cycle.
Substitute the values and on solving we get a time period.
2s1=2πT2{s^{ - 1}} = \dfrac{{2\pi }}{T}
T=πs\Rightarrow T = \pi s

\therefore The time period of oscillation is πs\pi s. Option (D) is the correct answer.

Additional information:
When a body is suspended from a fixed point with the help of a string in such a way that it can move to and fro, we call it a pendulum.
In the case of a simple pendulum, we assume all its mass is in the bob. The string with which it is hung is mass-less. With this pendulum, it is easy to study harmonic motion.

Note:
A simple pendulum is a simple harmonic oscillator when the restoring force acting on it is directly proportional to the displacement. Also for a pendulum to act as a simple harmonic oscillator displacement angle should be small.