Question

A pendulum has time period T. If it is taken on to another planet having acceleration due to gravity half and mass 9 times that of the earth then its time period on the other planet will be

• A. $\sqrt{T}$
• B. T
• C. $T^{1/3}$
• D. $\sqrt{2}$T

Answer 1

Answer: (D)

$\sqrt{2}$T

Answer 2

$T = 2\pi\sqrt{\frac{l}{g}} \Rightarrow T \propto \frac{1}{\sqrt{g}} \Rightarrow \frac{T_{P}}{T_{e}} = \sqrt{\frac{g_{e}}{g_{P}}} = \sqrt{\frac{2}{1}} \Rightarrow T' = \sqrt{2}T$