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Question

Chemistry Question on Bohr’s Model for Hydrogen Atom

A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368kHz1,368\, kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light, c=3.0×108ms1]\left.c=3.0 \times 10^{8} ms ^{-1}\right]

A

219.3 m

B

219.2 m

C

2192 m

D

21.92 cm

Answer

219.3 m

Explanation

Solution

λ=cV\lambda=\frac{c}{V} =3×108ms11368×103S1=\frac{3 \times 10^{8} ms ^{-1}}{1368 \times 10^{3} S ^{-1}} =219.3m=219.3\, m