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Question: A particular star (assuming it as a black body) has a surface temperature of about \(5 \times 10 ^ ...

A particular star (assuming it as a black body) has a surface temperature of about 5×104K5 \times 10 ^ { 4 } K The wavelength in nanometers at which its radiation becomes maximum is (b = 0.0029 mK)

A

48

B

58

C

60

D

70

Answer

58

Explanation

Solution

According to Wein’s displacement law

λmT=b\lambda _ { m } T = b or λm=bT\lambda _ { m } = \frac { b } { T } =0.00295×104=58×10−9 m=58 nm= \frac { 0.0029 } { 5 \times 10 ^ { 4 } } = 58 \times 10 ^ { - 9 } \mathrm {~m} = 58 \mathrm {~nm}