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Question

Mathematics Question on Differential equations

A particular solution of the equation logdydx=3x+4y,y(0)=0\log\frac{dy}{dx}=3x+4y,y(0)=0 is

A

4e3x+3e4y=7 4e^{3x} + 3e^{-4y }= 7

B

e3x+e4y=4 e^{3x} + e^{-4y }= 4

C

3e3x+e4y=7 3e^{3x} + e^{4y }= 7

D

none of these.

Answer

4e3x+3e4y=7 4e^{3x} + 3e^{-4y }= 7

Explanation

Solution

Answer (a) 4e3x+3e4y=7 4e^{3x} + 3e^{-4y }= 7