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Physics Question on Moving charges and magnetism

A particle with charge q moves with a velocity v in a direction perpendicular to the directions of uniform electric and magnetic fields, E and B respectively, which are mutually perpendicular to each other. Which one of the following gives the condition for which the particle moves undeflected in its original trajectory?

A

v=EBv =\frac{E}{B}

B

v=BEv=\frac{B}{E}

C

v=EBv=\sqrt{\frac{E}{B}}

D

v=qBEv=q\frac{B}{E}

Answer

v=EBv =\frac{E}{B}

Explanation

Solution

qE=qvB∴v=EBqE=qvB\therefore v=\frac{E}{B}