Question
Question: A particle which is simultaneously subjected to two perpendicular simple harmonic motions are repres...
A particle which is simultaneously subjected to two perpendicular simple harmonic motions are represented by: x=a1cosωt and y=a2cos2ωt traces a curve given by,
a)
b)
c)
d)
Solution
In the question it is given to us how the particle executes S.H.M along the x-axis and they-axis. Basically we are asked to find the path or the curve traced by the particle performing SHM along both the perpendicular axes. Hence we will obtain the relation between x and the y and accordingly determine the curve traced by the particle.
Complete answer:
It is given to us that particle is simultaneously subjected to two perpendicular simple harmonic motions which are represented by: x=a1cosωt and y=a2cos2ωt. Our basic aim is to determine the relation between x and y.
As per the trigonometric identity,
Cos2θ=2Cos2θ−1
Hence using this identity in the equation of motion of the particle along y we get,
y=a2cos2ωt⇒y=a2(2cos2ωt−1), ∵a1x=cosωt⇒y=a2(2(a1x)2−1)⇒y=2a2((a1x)2−21)
If we consider the above equation it represents the equation of a parabola which is facing upwards.
Hence we can say that the correct answer of the above question is option a.
Note:
In the above question we obtained the equation of the parabola. This can basically be understood by the power of the of x which is 2. Therefore we can say that the equation is a quadratic equation. If x or y both are expressed raised to some power of each other where power is equal to 2 then we can say that the curve basically represents a parabola. It is also to be noted that we need to know the different equations of parabola, when placed differently about its fixed point in order to determine the position of the curve.